Definition:
The Binomial Distribution is one of the discrete probability distribution. It is used when there are exactly two mutually exclusive outcomes of a trial. These outcomes are appropriately labeled Successand Failure. The Binomial Distribution is used to obtain the probability of observing r successes in n trials, with the probability of success on a single trial denoted by p.
Formula:
P(X = r) = nCr p r (1-p)n-r
where,
n = Number of events
r = Number of successful events.
p = Probability of success on a single trial.
nCr = ( n! / (n-r)! ) / r!
1-p = Probability of failure.
Example: Toss a coin for 12 times. What is the probability of getting exactly 7 heads.
Step 1: Here,
Number of trials n = 12
Number of success r = 7 since we define getting a head as success
Probability of success on any single trial p = 0.5
Step 2: To Calculate nCr formula is used.
nCr = ( n! / (n-r)! ) / r!
= ( 12! / (12-7)! ) / 7!
= ( 12! / 5! ) / 7!
= ( 479001600 / 120 ) / 5040
= ( 3991680 / 5040 )
= 792
Step 3: Find pr.
pr = 0.57
= 0.0078125
Step 4: To Find (1-p)n-r Calculate 1-p and n-r.
1-p = 1-0.5 = 0.5
n-r = 12-7 = 5
Step 5: Find (1-p)n-r.
= 0.55 = 0.03125
Step 6: Solve P(X = r) = nCr p r (1-p)n-r
= 792 * 0.0078125 * 0.03125
= 0.193359375
The probability of getting exactly 7 heads is 0.19
The Binomial Distribution is one of the discrete probability distribution. It is used when there are exactly two mutually exclusive outcomes of a trial. These outcomes are appropriately labeled Successand Failure. The Binomial Distribution is used to obtain the probability of observing r successes in n trials, with the probability of success on a single trial denoted by p.
Formula:
P(X = r) = nCr p r (1-p)n-r
where,
n = Number of events
r = Number of successful events.
p = Probability of success on a single trial.
nCr = ( n! / (n-r)! ) / r!
1-p = Probability of failure.
Example: Toss a coin for 12 times. What is the probability of getting exactly 7 heads.
Step 1: Here,
Number of trials n = 12
Number of success r = 7 since we define getting a head as success
Probability of success on any single trial p = 0.5
Step 2: To Calculate nCr formula is used.
nCr = ( n! / (n-r)! ) / r!
= ( 12! / (12-7)! ) / 7!
= ( 12! / 5! ) / 7!
= ( 479001600 / 120 ) / 5040
= ( 3991680 / 5040 )
= 792
Step 3: Find pr.
pr = 0.57
= 0.0078125
Step 4: To Find (1-p)n-r Calculate 1-p and n-r.
1-p = 1-0.5 = 0.5
n-r = 12-7 = 5
Step 5: Find (1-p)n-r.
= 0.55 = 0.03125
Step 6: Solve P(X = r) = nCr p r (1-p)n-r
= 792 * 0.0078125 * 0.03125
= 0.193359375
The probability of getting exactly 7 heads is 0.19
Binomial Distribution Problems
(1) A company
owns 400 laptops. Each laptop has an 8%
probability of not working. You randomly
select 20 laptops for your salespeople.
(a) What is the likelihood that 5 will be broken? (b) What is the likelihood that they
will all work?
(c) What is the likelihood that they will all be
broken?
(2) A study indicates that 4% of American teenagers
have tattoos. You randomly sample 30
teenagers. What is the likelihood that
exactly 3 will have a tattoo?
(3) An XYZ cell
phone is made from 55 components. Each
component has a .002 probability of being defective. What is the probability
that an XYZ cell phone will not work
perfectly?
(4) The ABC
Company manufactures toy robots. About
1 toy robot per 100 does not work. You
purchase 35 ABC toy robots. What is the probability that exactly 4 do not work?
(5) The LMB
Company manufactures tires. They claim
that only .007 of LMB tires are defective.
What is the probability of finding 2 defective tires in a random sample
of 50 LMB tires?
(6) An HDTV is
made from 100 components. Each component
has a .005 probability of being defective. What is the probability that an HDTV
will not work perfectly?
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(1) (a) 20C5 (.08)5
(.92)15 = .0145 (b) 20C0
(.08)0(.92)20 = .1887
(c) 20C20 (.08)20(.92)0 = .0000000000000000000001 (note -22 means move the decimal 22 places to the left)
(c) 20C20 (.08)20(.92)0 = .0000000000000000000001 (note -22 means move the decimal 22 places to the left)
(2) 30C3 (.04)3 (.96)27 = .0863
(3) Probability that it will
work (0 defective components) 55C0 (.002)0
(.998)55 = .896
Probability that it will not
work perfectly is 1 - .896 = .104 or
10.4%
(4) 35C4 (.01)4 (.99)31 = .00038
(5) 50C2 (.007)2 (.993)48 = .0428
(6) Probability that it will work (0 defective components) 100C0 (.005)0 (.995)100 = .606
(6) Probability that it will work (0 defective components) 100C0 (.005)0 (.995)100 = .606
Probability that it will not
work perfectly is 1 - .606 = .394 or
39.40%
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